x+2x^2=1225

Solution for x+2x^2=1225 equation:

x+2x^2=1225

We move all terms to the left:

x+2x^2-(1225)=0

a = 2; b = 1; c = -1225;
Δ = b2-4ac
Δ = 12-4·2·(-1225)
Δ = 9801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9801}=99$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-99}{2*2}=\frac{-100}{4}
=-25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+99}{2*2}=\frac{98}{4}
=24+1/2
$